Field notes, v1444
Page 166
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Transcription
[illegible] (200, 3) - (17.4 + 1 = 003, 035) pas->k ? : p=0 natu? x9 c+ = 003 o:28? p=0 natur? = p=et mtl j-7t2 mtl ogga[w dten 5. jain dat skit, x9 2 = - mlv2 kntd idatx,mtl,dat skit: (1- ad) kdnd-kld p=0 natu? : 1 - mtl p,(t+ld) Amd 3 c2 4e pc=mtl=-E (0dnti thg wpp. tking T = (712 mt) F - mntz kndr - 4/;k; p=0 natu? :1 - mntz, nd? pd,kndng xus (36y mt) ? 5 - 4-07d p=0 natu? :21, mtl was-E (Ctld) (W,mx) d ,+2k(1+2 kng to f1. mx)+2 - nds (1 dat kng j. 1 dcl. mt) x9 1 - 7 T lpsw. nmd? one skndnt ? - problem (p=0 natu?) :53, x1- (14. mtl and thdnt) (1pc mtl) ? , (712, mt) ! (79 dat kng j. 1 dcl. mt) ? = 1, 4, 8 ? (xmti kng .w) ? - ndvcd? nd- skt skit? = mny of th, p=0 A -2d dnt knwg, (712. mt) g2o - Emtl kdnd a B dt Ad, m9 (74c-mtl kngfwd) 1 - qus ? natu & km? . +2 mtl 2 (yct mt) 2 skt skit?, x. mny, x9 1 - qus 2 ntts p=0 natu? : - mlb3..C A: A (intwld 1- wh, 3 p=0) qus, 3, pc? ? E. "B.s - kndg mny g1 xH 4+6, p=0 natu? : skt skit W kng 1 = mngs 2kD) (751, mt +) ? (1 - ndvcd? p=m? -0d,kndt3 1 - , thdntm apprd skt x:d? : (1 - kdntdy?) skt skit: 1 - mngwgrA ad kx2